X^2+25x-12=0

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Solution for X^2+25x-12=0 equation:



X^2+25X-12=0
a = 1; b = 25; c = -12;
Δ = b2-4ac
Δ = 252-4·1·(-12)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{673}}{2*1}=\frac{-25-\sqrt{673}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{673}}{2*1}=\frac{-25+\sqrt{673}}{2} $

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